Making Numbers 3

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Look at this situation: 1 1 1 1 = 6.

We can make this a correct equality by inserting different number operations. For instance

(1 + 1 + 1)! × 1 = 6

Note that !, pronounced factorial, works this way:
2! = 2 × 1
3! = 3 × 2 × 1
4! = 4 × 3 × 2 × 1, etc.

Which of the following can you complete by inserting various common number operations?
(i) 2 2 2 2 = 6
(ii) 3 3 3 3 = 6
(iii) 4 4 4 4 = 6
(iv) 5 5 5 5 = 6
(iv) 6 6 6 6 = 6
(vi) 7 7 7 7 = 6

Solution: