Making Numbers 3

Thanks for visiting NZMaths.
We are preparing to close this site by the end of August 2024. Maths content is still being migrated onto Tāhūrangi, and we will be progressively making enhancements to Tāhūrangi to improve the findability and presentation of content.
 

For more information visit https://tahurangi.education.govt.nz/updates-to-nzmaths

Look at this situation: 1 1 1 1 = 6.

We can make this a correct equality by inserting different number operations. For instance

(1 + 1 + 1)! × 1 = 6

Note that !, pronounced factorial, works this way:
2! = 2 × 1
3! = 3 × 2 × 1
4! = 4 × 3 × 2 × 1, etc.

Which of the following can you complete by inserting various common number operations?
(i) 2 2 2 2 = 6
(ii) 3 3 3 3 = 6
(iii) 4 4 4 4 = 6
(iv) 5 5 5 5 = 6
(iv) 6 6 6 6 = 6
(vi) 7 7 7 7 = 6

Solution: