3-4
4 weeks
This is a level 4 number activity from the Figure It Out series. It relates to Stage 7 of the Number Framework.
A PDF of the student activity is included.
Click on the image to enlarge it. Click again to close. Download PDF (827 KB)
use place value strategies to solve multiplication problems
use tidy numbers strategies to solve multiplication problems
use doubling and halving strategies to solve multiplication problems
Number Framework Links
Use this activity to help students consolidate and compare advanced multiplicative part–whole strategies (stage 7) in the domain of multiplication and division.
A classmate
See the notes for Bean Counters (page 21) on the reasons for students having and using a broad range of multiplicative strategies.
For this activity, students need to be already familiar with the following multiplicative strategies:
• Place value partitioning: partitioning a number (using place value), multiplying the parts separately, and then adding the products.
5 x 48 = (5 x 40) + (5 x 8)
= 200 + 40
= 240
(see Sticking Together, pages 10–11)
• Using tidy numbers and compensating: working out 5 x 50 instead of 5 x 48 because 50 is a tidy number and easy to multiply. But then we have to compensate because we have got 5 groups of 2 more than we need, so we subtract them again.
5 x 48 = (5 x 50) – (5 x 2)
= 250 – 10
= 240
(see Bean Counters, pages 8–9)
• Doubling and halving (making proportional adjustments): doubling one factor and halving the other gives you the same answer and may make the calculation easier.
5 x 48 = 10 x 24
= 240
(see Face the Facts in Multiplicative Thinking, Figure It Out, Levels 2–3, page 6).
This activity is suited to a guided teaching session with a group because there are lots of opportunities for discussion. Introduce the activity by getting your students to solve Mr Mannering’s problem before they look at how the students in the book solve it. Discuss the different strategies your group used and use this discussion as an opportunity to remind the students of the meaning of the terms “place value”, “tidy numbers”, and “doubling and halving”.
The aim of this activity is to help the students learn to make wise decisions about which strategy to use in a particular situation. In order to do this, they need to be able to look at a problem before they solve it and identify features that would prompt them to use one strategy rather than another.
Promote generalisations by asking questions such as:
• Look at the problem before you start working it out; which strategy do you think would be most efficient here?
• What is it about this problem that makes you want to use that strategy?
• List all the problems in the activity and group them according to the strategy you thought was most efficient for each problem. (It may be valid to have some problems in two groups if both strategies are equally efficient for those problems.)
• What do all the problems in each group have in common?
Useful responses will include these ideas:
Doubling and halving: This strategy is useful if it can change the calculation into a known fact or one that is easy to work out, such as 10 times. At least one of the factors should be even so that halving it gives us a whole number.
Tidy numbers and compensating: One of the factors has to be close to a tidy number so there isn’t too much compensating to do.
Place value partitioning: This strategy suits a wide range of problems, but it can be difficult to keep track of if there’s a lot of renaming to do when you’re adding up the parts. It’s easier to use if the digits are small.
Extension
Students could create a flow diagram that shows what they would look for when confronted with a problem and how their strategy decision-making process might progress. They could start by asking “Is the answer to this problem a known fact?” and then ask questions such as “Is the problem 5 times or 50 times something?” If the answer is yes, “Use doubling and halving to create a 10 times or 100 times problem and solve it”; if the answer is no, “Would doubling and halving the problem turn it into a known fact?” and so on.
1. a. i. Manua
ii. Sophie
iii. Larry
b. Answers may vary. Manua’s method involved the simplest calculations and was very efficient in this case.
2. a. i. (5 x 100) – (5 x 2) = 500 – 10 = 490
ii. (5 x 90) + (5 x 8) = 450 + 40 = 490
iii. 5 x 98 = 10 x 49 = 490
b. Answers may vary. Sophie’s method involved the simplest calculations and was very efficient.
3. a. Discussion and choice of methods will vary.
i. This would be a good problem for using doubling and halving, because doubling
5 times makes it into 10 times, which is easy to calculate, and the other factor
is an even number, which is easy to divide. The other two methods would
also work well but involve slightly more calculations (using tidy numbers and
place value).
ii. This would be a good problem for using place value to break up the 43. Using
tidy numbers is also possible, but 43 is not very close to a tidy number so the
calculation is a little harder. Doubling and halving is not useful in this case:
both numbers are odd, so it doesn’t help to halve one of them.
iii. This would be a good problem for using tidy numbers because the 79 is very
close to a tidy number. Doubling and halving won’t help. 79 could be broken
up using place value, but the calculations will be more difficult than calculations
using a tidy number.
b. Discussion about the most efficient method will vary. Possible working for each problem is:
i. Tidy numbers
5 x 26 =
5 x 26 = (5 x 30) – (5 x 4)
= 150 – 20
= 130
Place value
5 x 26 = (5 x 20) + (5 x 6)
= 100 + 30
= 130
Doubling and halving
5 x 26 = 10 x 13
= 130
ii. Tidy numbers
43 x 7 =
43 x 7 = (50 x 7) – (7 x 7)
= 350 – 49
= 301
Place value
43 x 7 = (40 x 7) + (3 x 7)
= 280 + 21
= 301
Doubling and halving
43 x 7 = 86 x 3.5 = 301 or 21.5 x 14 = 301 so 43 x 7 = 301. (In both cases, this
strategy makes the calculation harder, not easier.)
iii. Tidy numbers
6 x 79 =
6 x 79 = (6 x 80) – (6 x 1)
= 480 – 6
= 474
Place value
6 x 79 = (6 x 70) + (6 x 9)
= 420 + 54
= 474
Doubling and halving
6 x 79 = 12 x 39.5
= 474
(This strategy makes the calculation harder, not easier.)
4. a. Problems will vary.
i. The problem should have one number that is close to a tidy number to make
it easy to solve.
ii. This strategy suits many problems, but it’s the easiest to use if one number in the
problem is a single-digit number and there isn’t much renaming involved.
iii. This strategy suits 5 times or 50 times problems because these numbers double
to make 10 times or 100 times, which are easy to calculate with. Other problems suit
this strategy if they can be changed into known facts, for example:
4 x 16 = 8 x 8 = 64.
b. Practical activity. See points in 4a.
This is a level 3 number and algebra strand activity from the Figure It Out series. It relates to Stage 6 of the Number Framework.
A PDF of the student activity is included.
Click on the image to enlarge it. Click again to close. Download PDF (174 KB)
use basic facts to solve equations
FIO, Level 2-3, Basic Facts, 31 or None, page 4
At least 2 classmates to play with
This activity is based on an ancient Chinese game in which players had to make given totals by using four single-digit numbers and the four operations. Thirty-one is a good target as there are many ways in which students can reach this score. Students could use a tally sheet to record who has the highest score in each round.
After students have played the game several times, the target number can be changed. Students may wish to describe why it is easier to get a target of 31 than a target of 13. Similarly, they can be given a target total such as 27 and asked to write as many four-digit combinations for it as they can.
For example:
Where students use different types of calculators, particularly scientific and four-function, the issue of order for operations may arise. For example, given 4 + 6 x 3 – 5 = , a scientific calculator will get 17 whereas a four-function calculator will get 25. Four-function calculators perform calculations in the order of keying, that is, 4 + 6 = 10, then 10 x 3 = 30, and then 30 – 5 = 25.
A scientific calculator uses the convention for operations, that is, multiplication and division are calculated before addition and subtraction. With 4 + 6 x 3 – 5 = , the 6 x 3 = 18 is performed first, and then 4 is added and 5 subtracted: 18 + 4 – 5 = 17.
Students will need to approach this systematically. A table would be useful.
Game
Game of addition, subtraction, multiplication, and division
Activity
64 plums
The purpose of this activity is to engage students in using their number knowledge and skills to solve a problem requiring partitioning.
This activity assumes the students have experience in the following areas:
The problem is sufficiently open ended to allow the students freedom of choice in their approach. It may be scaffolded with guidance that leads to a solution, and/or the students might be given the opportunity to solve the problem independently.
The example responses at the end of the resource give an indication of the kind of response to expect from students who approach the problem in particular ways.
Bill puts exactly $27 into his piggy bank every month.
It takes one year and seven months to fill. How much money will Bill have in his full piggy bank?
The following prompts illustrate how this activity can be structured around the phases of the Mathematics Investigation Cycle.
Introduce the problem. Allow students time to read it and discuss in pairs or small groups.
Discuss ideas about how to solve the problem. Emphasise that, in the planning phase, you want students to say how they would solve the problem, not to actually solve it.
Allow students time to work through their strategy and find a solution to the problem.
Allow students time to check their answers and then either have them pair share with other groups or ask for volunteers to share their solution with the class.
The student combines additive and multiplicative thinking to solve the problem.
Click on the image to enlarge it. Click again to close.
The student applies the distributive property of whole numbers under multiplication to solve the problem. They round the multiplier and adjust the product correctly.
This unit explores situations that involve multiplication and division using an equal sets model. Students learn to apply the properties of whole numbers under multiplication, to derive new answers from basic facts, and apply inverse operations to division.
In te reo Māori the word for multiplication is whakarea. Whaka means “to happen” and rea means “grow or make plentiful” like the offshoots of a plant. The word whakarea captures the scaling nature of multiplication, meaning the creation of many copies of equal sets.
The simplest form of multiplication problem involves finding the total of a given number of equal sets. Consider this problem:
There are eight cartons of eggs. Each carton contains four eggs.
How many eggs are there altogether?
The problem can be represented mathematically as 8 x 4 = □. Eight represents the number of sets (the multiplier). Four is the number in each set (multiplicand) and represents the unit rate of “four eggs per carton.” The x symbol represents “of” in the sense of connecting eight sets of four. The empty box is the product or total and the equals sign represents sameness of quantity or balance.
Division with equal sets takes two forms depending on which factor is unknown. The te reo Māori word for division is whakawehe which means “to make separation happen”. The separation into equal sets happens in two different situations.Sharing division comes for equally distributing a total number of objects, the dividend, into a given number shares (the divisor), which results in an amount per share (the quotient). For example:
There are 32 eggs and eight cartons of the same size.
How many eggs go into each carton?
Note that 32 ÷ 8 = 4 represents the sharing of 32 (the dividend) into 8 equal sets (the divisor) which results in a quotient of “4 eggs per carton.” Division also applies to measurement contexts such as:
There are 32 eggs. Four eggs go into each carton.
How many cartons are needed?
Note that the rate is known, “4 eggs per carton”, and that becomes the unit of measure. “How many fours are in 32?” answers the problem. That can be written as 32 ÷ 4 = 8.
Both equal sharing and measuring problems are common in the real world. Developmentally, students tend to build up solutions to these problems using addition at first, progressing to multiplication. With appropriate opportunities to learn, students later come to treat division as an operation in its own right.
The learning opportunities in this unit can be differentiated by providing or removing support to students and by varying the task requirements. Ways to differentiate include:
The context used for this unit is bacon and eggs, simply to provide everyday situations that students are likely to be familiar with. You may wish to change the contexts to situations more relevant to your students’ everyday lives, interests, or cultural identities. For example, eggs in cartons might become kumara in kete, players per team, rowers in a waka ama, or students in mini-buses. Encourage students to be creative by accepting a variety of strategies, and asking them to create their own problems for others to solve, in contexts that are meaningful.
In this session students transfer the strategies they developed for multiplication to problems involving division. Understanding that asking themselves the question, “How many x’s fit in y?” structures division problems and supports students’ fluency in calculation. By connecting division to multiplication students learn to apply their multiplication strategies and connect multiplication and division as inverse operations.
In this session students explore an open-ended problem that allows them to demonstrate their multiplication and division strategies. The problem requires them to impose or find some information, i.e., the number of hens, how many eggs hens lay per week, and the size of the trays. Invite them to research online if they need to and use their knowledge of everyday context, e.g., trays that eggs commonly come in.
Dear family and whānau,
This week at school we are learning to solve multiplication and division problems. The problems are all about eggs with a little bacon.
Here is an example:
Henrietta has 72 eggs that she wants to put into six-packs.
How many packs can she make?
We encourage children to use multiplication knowledge rather than adding on because multiplication is more efficient. For example, it is more efficient to work out how many sixes are in 72 than to keep adding six until 72 is found.
Printed from https://nzmaths.co.nz/user/1117/planning-space/mult-div-0 at 12:19am on the 4th July 2024