This activity has a logic and reasoning focus.
This problem develops two concepts. The first is counting all possible arrangements, and the second is noticing that some of these arrangements are ‘alike' and so might be considered to be the same.
The first part of this problem has students following these steps:
The students should be encouraged to try to find a number of answers and to reach a point where they have some systematic idea as to why there are no more answers. There three important skills that are fundamental to all of mathematics (and maybe life itself); first being able to find some possibilities, then getting all possibilities and then justifying that there are no more. We work through this sequence in the Solution.
The second idea in this problem is symmetry. This involves noticing that turning some arrangements of the milk cartons through quarter turns, will give another arrangement. The two arrangements are said to be ‘alike'. The aim is to find such arrangements, put them into groups and find how many such groups there are. This will confirm the number of different arrangements, or the number of groups that are not ‘alike'.
This problem is one of a series of 8 based around the theme of no-three-in-a-line. The other lessons in this sequence are Strawberry and Chocolate Milk, Level 1; Three-In-A-Line, Level 2; No Three-In-A-Line, Level 3; More No-Three-In-A-Line, Level 4; No-Three-In-A-Line Again, Level 5; No-More-In-A-Line; Level 6 and No-Three-In-A-Line Game, Level 6. The problems increase in difficulty through the sequence and the skills discovered in one problem are used in the next. There is a web site on the no-three-in-line problem. Its url is www.uni-bielefeld.de/~achim/no3in/readme.html The material in this web site is too complicated for Level 1 students but it may be of interest to you. It shows a problem that mathematicians are working on right now and still can’t solve.
Strawberry and Chocolate Milk is another Level 1 problem your students may enjoy.
Hannah has a square milk crate that can hold four cartons. In how many ways can she put two strawberry milk cartons into the crate?
Hannah found a slightly bigger crate. This one had room for 9 cartons. In how many ways can she put 8 strawberry milk cartons into her new crate?
The students may use a drawing or equipment to solve the problem. They are likely to approach this unsystematically at first. For example:
The question is, are there any more?
To answer that question we need to be systematic. Draw it so that nothing is missed. One way to do this is to first put one milk carton in the top left-hand corner of the crate and then move the other around the crate from one possible arrangement to the next. This will give us the following possibilities.
There are only three ways of doing this. We’ve now exhausted all possibilities for a bottle in the top left-hand corner of the crate. So now move on to the top right hand corner.
So there are only two new possibilities here. We list them below.
Now let’s put the first bottle in the bottom left-hand corner. This gives us only one new answer.
Any other arrangement that has a bottle in the bottom left-hand corner, forces the other bottle to be in a position we’ve already considered. By being systematic, we’ve accomplished the last two steps of the problem. We’ve got all possible answers (step (ii)) and we’ve shown that these are all there are (step (iii)).
Here are the six possible answers.
Do some of the six answers above look the same? Do some of them look different?
3 and 5 look more like each other than 1, 2, 4, and 6. You see 2 and 5 show bottles opposite each other while in 1, 2, 4, and 6 the two bottles are on the same side of the crate.
Ask students to model rotations of the square crate that would produce arrangements that are 'alike'.
There are two groups of ‘alike' arrangements. These are 3 and 5, and 1, 2, 4, and 6. Therefore there are only two arrangements of the cartons in the crate and every other arrangement comes from one of these just by rotating the crate. These two arrangements are represented by the non-alike crates of Charlie and Hine.
The easiest way to be systematic is to look at where the space without a bottle can be. Take it systematically round the crate starting at, say, the top left-hand corner of the crate. There are 9 possibilities.
Then consider the notion of ‘alike'.
You can see that 1, 3, 7, and 9 are 'alike'. They all have a corner square free. You can rotate any one of these crates through a quarter turn onto any of the others.
Second, 2, 4, 6, and 8 are alike. They all have the middle square on a side empty. Again you can rotate from any one of these to any other.
Finally 5 is on its own. It has the centre space vacant. When you rotate it, the centre space stays in the centre. It can't be matched up to any other arrangement.
There are three distinct groups of answers under rotation. These are represented by the arrangements 1, 2 and 5.
You may like to consider the properties of the arrangements.
Are there any crates that stay the same after a rotation of a quarter turn?
Are there any crates that stay the same after a rotation of a half turn?
Consider further variations on the crate size and the number of cartons.
Printed from https://nzmaths.co.nz/resource/strawberry-milk-0 at 7:18am on the 20th January 2021