This problem solving activity has a measurement focus.
Moana set her digital watch at 13:00:00 on the last day of April.
Unfortunately the watch loses 11 seconds a day.
What is the time on Moana’s watch when it is 13:00:00 on the last day of May?
- Convert seconds to minutes.
- Subtract minutes and seconds using a 24-hour clock.
- Devise and use problem solving strategies to explore situations mathematically (be systematic).
To solve this problem students must know the number of days in each month, that there are 60 minutes in an hour, that there are 60 seconds in a minute, and must be able to work between units of time.
- Copymaster of the problem (English)
- Copymaster of the problem (Māori)
- Calendar
- Digital watch (to pose the problem)
The Problem
Moana set her digital watch at 13:00:00 on the last day of April. Unfortunately the watch loses 11 seconds a day. What is the time on Moana’s watch when it is 13:00:00 on the last day of May?
Teaching Sequence
- Pose the problem. Have students suggest adjustments they would need to make if their own watches lost 11 seconds each day.
- Confirm the number of days in May, the number of seconds in a minute, and the number of minutes in an hour.
- As the students work on the problem, ask questions that focus their thinking on the calculations that they are using.
How could we work this out systematically?
How did you work out the number of seconds the watch had lost?
Does your final answer seem reasonable? Why? How could you check? - Encourage the students to record their solutions for display at the end of the class.
- Share solutions.
Extension
What if the watch lost 11 seconds an hour. What would the time read on Moana's watch?
Solution
Since there are 31 days between the last day of April and the last day of May, Moana’s watch will have lost 31 x 11 = 341 seconds. To convert this into minutes, divide by 60. Hence 341 seconds = 5 minutes and 41 seconds. Then subtract 5 minutes 41 seconds from 13:00:00. This gives 12:54:19. This is the time on Moana’s watch.