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# Fitness

Achievement Objectives:

Achievement Objective: GM4-8: Use the invariant properties of figures and objects under transformations (reflection, rotation, translation, or enlargement).
AO elaboration and other teaching resources
Achievement Objective: GM4-5: Identify classes of two- and three-dimensional shapes by their geometric properties.
AO elaboration and other teaching resources

Purpose:

This unit examines regular tessellations, that is, tessellations that can be made using only one type of regular polygon, and semi-regular tessellations, where more than one type of regular polygon is involved. Students are required to investigate what properties tessellating shapes must have in order to cover the plane with no gaps or overlaps.

Specific Learning Outcomes:
• create regular and semi-regular tessellations of the plane
• demonstrate why a given tessellation will cover the plane
Description of mathematics:

Tessellations are frequently found in kitchen and bathroom tiles and lino. You can see them in the pattern on carpets and decorative patterns on containers and packaging. Tessellations are a neat and symmetric form of decoration. They also provide a nice application of some of the basic properties of polygons.

To be able to fully understand tessellations using regular polygons, you need to know about their symmetry and about the size of their interior angles. All of the facts that you need to know are accessible to Level 4 students. This unit takes children through the steps that they need in order to establish that there are only three regular polygons that tile the plane. This unit thus follows on from Keeping in Shape from Level 3, where regular tessellations are first discussed.

Moving on from here, the children can consider semi-regular tilings. All that they need to know here is how to sum the interior angles of various regular polygons to 360° . The rest is up to their imagination.

Required Resource Materials:
protractors, scissors, paper, rulers, pencils
pattern blocks or mosaic shapes
isometric dot paper
Copymaster 1 (table showing angles of regular polygons)
Copymaster 2 (templates of regular polygons from 3-sided to 12-sided)
Copymaster 3 (semi-regular tessellations)
Copymaster 4 (regular polygonal tessellations with different vertex arrangements)
Activity:

#### Getting Started

1. Show the students a large cut out equilateral triangle. Mark the vertices (corners) of the triangle with different colours. Say, "I am going to tear off the corners of this triangle and place them around this point (draw point on board). What do you think will happen?" Students may have encountered this before but let them guess what they think will happen. Tear off the corners and place them about the point to confirm that a half turn (or 180°) is created.

2. Ask them whether they think this will work for any triangle, no matter what shape it is (isosceles, scalene, obtuse). Is there a way to check this without tearing off the corners? (Measure the interior (inside) angles to see if they total 180º (a half turn).) Tell the students to make a variety of triangles and test this conjecture.
3. If the sum of the interior angles of any triangle is the same - 180º, is it likely that the sum of the interior angles of any quadrilateral is the same? Ask them to predict what will happen if the corners of any quadrilateral are joined about a point. Have them cut out several quadrilaterals of different shapes to check their predictions. Remind them to mark the corners before tearing them off.

4. Once it has been found that the sum of the interior angles of any quadrilateral is 360º (they form a full turn about a point), then students can investigate the sum of interior angles of other polygons by measuring with protractors or tearing corners. The results can be captured in the table below. Encourage the students to look for a pattern to predict what the next angular sum will be.
 Number of Sides Sum of Angles º Interior Angle of Regular Polygon 3 180 4 360 5 540 6 720

Note that for each side that is added, the sum of the interior angles increases by 180º. This can be explained by the fact that the addition of a side creates another triangle within the shape, and that each triangle has an angular sum of 180º.

 Quadrilateral (2 triangles) Pentagon (3 triangles) Hexagon (4 triangles)

5. Challenge the students to use their results to draw a regular triangle (equilateral), a regular quadrilateral (square), a regular pentagon, a regular hexagon, and a regular octagon. Regular means that all sides are the same length and all interior angles are equal.
6. What size are the interior angles of the regular figures we have just been talking about? How can we find out?

For the regular hexagon with six vertices and an angular sum of 720º, we need to divide the sum by the number of angles to find each angle size. So, since 720 ÷ 6 = 120, each interior angle in a regular hexagon is 120°.

7. Get the children to complete the table above for polygons with up to 12 sides. (The regular dodecagon (12-sided polygon) has an angular sum of 1800°, so each interior angle will be 150°.)

#### Exploring

1. Use a set of pattern blocks to show how equilateral triangles tessellate. Tessellate means that they cover the plane infinitely with no gaps or overlaps. Send the students away in groups with their own set of pattern blocks to explore what other tessellations can be discovered using shapes from the set. You may want them to record the tessellations using isometric dot paper.

After a period of exploration bring the class back together to share the tessellations. Note that there are three regular tessellations that can be found, that is tessellations involving use of the same regular polygon. These regular tessellations are 3.3.3.3.3.3 (six triangles about each point or vertex), 4.4.4.4 (four squares about each vertex), and 6.6.6 (three hexagons about each vertex).

2. Focussing on the regular tessellations ask why it is that these patterns work without gaps or overlaps. You may need to remind the students of the angle measures they found in Getting Started. There are two key properties of the shapes involved in regular tessellations:
• side lengths are the same;
• the sum of angles meeting at each vertex is exactly 360° (a full turn).
1. For example, in the case of the tessellation with squares (4.4.4.4), the side lengths are the same and the four angles of 90° add up to 360° .

Confirm that the "angles around a point" principle holds for the other tessellations that students have found.

1. Remind the students of the table on angle sums (Copymaster 1) that contains the interior angle measurements for regular polygons. Ask: From the table could we have expected the triangles, squares, and hexagons to have tessellated by themselves? How? (Each of these shapes has interior angles that can be divided into 360° evenly.)
2. Many other tessellations are possible with combinations of pattern block shapes. Get them to experiment with combinations of regular polygons. These tessellations are known as semi-regular tessellations. For example, from the table it looks like 2 squares and three triangles might fit together about a point because 90°+ 90°+ 60°+ 60°+ 60° = 360°.
3. These might be arranged in different ways, e.g. square-triangle-triangle-square-triangle (4.3.3.4.3) and square-square-triangle-triangle–triangle (4.4.3.3.3). Try to produce all possible combinations using pattern blocks.
4. Give the students Copymaster 2 that gives templates for the regular polygons up to the 12-sided shape (dodecagon). By stapling through the centre of each shape onto blank pages underneath students can make multiples of each regular polygon. Get them to use the table and the cut out shapes to find as many semi-regular tessellations as they can.
5. Share the results as a class to see if all the possible semi-regular tessellations have been found. These are 3.3.3.4.4, 3.6.3.6, 3.3.4.3.4, 3.3.3.3.6, 4.8.8, 3.4.6.4, 3.12.12, 4.6.12 (eight possibilities). Students may wish to create a poster presenting their favourite semi-regular tessellations explaining why each combination of shapes can tessellate the plane. Other tessellations are possible using regular polygons if the constraint of each vertex having the same arrangement of shapes is removed. For example, hexagons, squares and triangles can be used in this way.

Note that with some vertices the arrangement is 6.3.4.4 and at others it is 6.4.4.3 if the shapes are read clockwise about each vertex.

Get the students to investigate what other arrangements can be found in this way. Copymaster 4 contains examples of such arrangements. Note that this embodies the commutative principle seen in the square-square-triangle-triangle-triangle arrangements that changing the order of the addends does not affect their sum, in this case 360°.

#### Reflecting

1. Observation of the table might persuade them that tessellating combinations are not likely for the heptagon (7 sides), decagon (10 sides) and hendecagon (11 sides) since their interior angles measures will not yield combinations to 360°. Is it possible to show that there are only three regular tessellations?
2. There are two approaches for this depending on the ability of your students. The first way is to notice that no polygon has an interior angle greater than 180°. They are always less than this. And no polygon has an interior angle smaller than 60°. (You can see this intuitively from the table.) That means that you need at least three polygons to come together at a vertex (it has to be an integer more than 360/180) and no more than six (it has to be less than 360/60). So,

if it is 3, the interior angles have to be 360°/3 = 120°;
if it is 4, the interior angles have to be 360°/4 = 90°;
if it is 5, the interior angles have to be 360°/5 = 72°; and
if it is 6, the interior angles have to be 360°/6 = 60°.

Only three of these are possible for regular polygons. So the only tessellation by regular polygons requires an equilateral triangle, a square or a hexagon.

1. Alternatively, look at the size of interior angles. These have to be (n – 2) 180°/n for an n-sided regular polygon. And this angle has to divide 360°, so 360° divided by (n – 2) 180°/n has to be a whole number. So 2n/(n – 2) has to be a whole number. This can only happen if n = 3, 4 or 6. Perhaps the easiest way to see this is to rewrite 2n/(n – 2) as 2 + 4/(n – 2). Now we see that n – 2 has to divide 4. Hence n – 2 = 1, 2 or 4. So n = 3, 4 or 6.
AttachmentSize
FitnessCM1.pdf44.55 KB
FitnessCM2.pdf51.67 KB
FitnessCM3.pdf85.48 KB
FitnessCM4.pdf96.6 KB