This problem solving activity has a number (multiplication and division) focus.
On the pirate ship there are 24 pirate swords. Each pirate has 2 swords.
If half the pirates lost a sword in battle and a quarter of the pirates each gained a new sword, how many swords would there now be on the pirate ship?
If a third of the swords were then lost how many would there be left?
This problem helps students to think about how to solve a problem, how to plan their approach, and how to keep track of their work as they progress. In this problem, students have to use logic and be careful with their recording.
The problem requires students to have, and to develop, knowledge of the use of fractions in a practical situation. Problems such as this lay the foundation for algebra as different operations must be used together and in the correct combination to solve this problem. Algebra helps to sort out such problems and simplify them.
On the pirate ship there are 24 pirate swords. Each pirate has 2 swords.
If half the pirates lost a sword in battle and a quarter of the pirates each gained a new sword, how many swords would there now be on the pirate ship?
If a third of the swords were then lost how many would there be left?
Adjust fractions and numbers as appropriate for your students.
You may also find these pirate themed problems of interest: Cannon Balls or Treasure to Ship.
If each pirate has 2 of 24 swords, then there must be 12 pirates. If half the pirates (6) lost 1 sword in battle, this means they lost 6 swords. 6 swords are lost, leaving 18 swords (24 - 6 = 18).
The total number of pirates is 12. 12 divided by 4 is 3, meaning a quarter of the pirates is 3 pirates. If a quarter of the pirates gained a new sword, there would be 3 new swords, making 21 swords altogether.
One third of 21 (total number of swords) is 7. If 7 swords were lost, there would be 14 swords remaining (21 – 7 = 14).
Printed from https://nzmaths.co.nz/resource/pirate-swords at 1:54pm on the 19th April 2024